Solve (-1/2)(1/3)+1/4=

$$( - \frac { 1 } { 2 } ) ( \frac { 1 } { 3 } ) + \frac { 1 } { 4 } =$$

Evaluate

$$\frac{1}{12}\approx 0.083333333$$

Solution Steps

Multiply -\frac{1}{2} times \frac{1}{3} by multiplying numerator times numerator and denominator times denominator.

$$\frac{-1}{2\times 3}+\frac{1}{4}$$

Do the multiplications in the fraction \frac{-1}{2\times 3}.

$$\frac{-1}{6}+\frac{1}{4}$$

Fraction \frac{-1}{6} can be rewritten as -\frac{1}{6} by extracting the negative sign.

$$-\frac{1}{6}+\frac{1}{4}$$

Least common multiple of 6 and 4 is 12. Convert -\frac{1}{6} and \frac{1}{4} to fractions with denominator 12.

$$-\frac{2}{12}+\frac{3}{12}$$

Since -\frac{2}{12} and \frac{3}{12} have the same denominator, add them by adding their numerators.

$$\frac{-2+3}{12}$$

Add -2 and 3 to get 1.

$$\frac{1}{12}$$

Factor

$$\frac{1}{2 ^ {2} \cdot 3} = 0.08333333333333333$$