Solve ((n+1)+1)^1-6

$$( ( n + 1 ) + 1 ) ^ { 1 } - 6$$

Evaluate

$$n-4$$

Solution Steps

Add 1 and 1 to get 2.

$$\left(n+2\right)^{1}-6$$

Calculate n+2 to the power of 1 and get n+2.

$$n+2-6$$

Subtract 6 from 2 to get -4.

$$n-4$$

Differentiate w.r.t. n

$$1$$

Steps Using Derivative Rule for Sum

Add 1 and 1 to get 2.

$$\frac{\mathrm{d}}{\mathrm{d}n}(\left(n+2\right)^{1}-6)$$

Calculate n+2 to the power of 1 and get n+2.

$$\frac{\mathrm{d}}{\mathrm{d}n}(n+2-6)$$

Subtract 6 from 2 to get -4.

$$\frac{\mathrm{d}}{\mathrm{d}n}(n-4)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$n^{1-1}$$

Subtract 1 from 1.

$$n^{0}$$

For any term t except 0, t^{0}=1.

$$1$$