Solve ((f)3/x+3=4

$$( ( f ) \frac { 3 } { x + 3 } = 4$$

Solve for f

$$f=\frac{4\left(x+3\right)}{3}$$

$$x\neq -3$$

Steps for Solving Linear Equation

Multiply both sides of the equation by x+3.

$$f\times 3=4\left(x+3\right)$$

Use the distributive property to multiply 4 by x+3.

$$f\times 3=4x+12$$

The equation is in standard form.

$$3f=4x+12$$

Divide both sides by 3.

$$\frac{3f}{3}=\frac{4x+12}{3}$$

Dividing by 3 undoes the multiplication by 3.

$$f=\frac{4x+12}{3}$$

Divide 12+4x by 3.

$$f=\frac{4x}{3}+4$$

Solve for x

$$x=\frac{3\left(f-4\right)}{4}$$

$$f\neq 0$$

Steps for Solving Linear Equation

Variable x cannot be equal to -3 since division by zero is not defined. Multiply both sides of the equation by x+3.

$$f\times 3=4\left(x+3\right)$$

Use the distributive property to multiply 4 by x+3.

$$f\times 3=4x+12$$

Swap sides so that all variable terms are on the left hand side.

$$4x+12=f\times 3$$

Subtract 12 from both sides.

$$4x=f\times 3-12$$

The equation is in standard form.

$$4x=3f-12$$

Divide both sides by 4.

$$\frac{4x}{4}=\frac{3f-12}{4}$$

Dividing by 4 undoes the multiplication by 4.

$$x=\frac{3f-12}{4}$$

Divide -12+3f by 4.

$$x=\frac{3f}{4}-3$$

Variable x cannot be equal to -3.

$$x=\frac{3f}{4}-3\text{, }x\neq -3$$