Solve ((c)+galpha=5/13

$$( ( c ) + g \alpha = \frac { 5 } { 13 }$$

Solve for g

$$\left\{\begin{matrix}g=-\frac{13c-5}{13\alpha }\text{, }&\alpha \neq 0\\g\in \mathrm{R}\text{, }&c=\frac{5}{13}\text{ and }\alpha =0\end{matrix}\right.$$

Steps for Solving Linear Equation

Subtract c from both sides.

$$g\alpha =\frac{5}{13}-c$$

The equation is in standard form.

$$\alpha g=\frac{5}{13}-c$$

Divide both sides by \alpha .

$$\frac{\alpha g}{\alpha }=\frac{\frac{5}{13}-c}{\alpha }$$

Dividing by \alpha undoes the multiplication by \alpha .

$$g=\frac{\frac{5}{13}-c}{\alpha }$$

Divide \frac{5}{13}-c by \alpha .

$$g=\frac{5-13c}{13\alpha }$$

Solve for c

$$c=\frac{5}{13}-g\alpha$$

Solution Steps

Subtract g\alpha from both sides.

$$c=\frac{5}{13}-g\alpha$$