Solve ((273/10-13,4*2):(-1/8)-12)*3

$$( ( 27 \frac { 3 } { 10 } - 13,4 \cdot 2 ) : ( - \frac { 1 } { 8 } ) - 12 ) \cdot 3$$

Evaluate

$$-48$$

Solution Steps

Multiply 27 and 10 to get 270.

$$\left(\frac{\frac{270+3}{10}-13,4\times 2}{-\frac{1}{8}}-12\right)\times 3$$

Add 270 and 3 to get 273.

$$\left(\frac{\frac{273}{10}-13,4\times 2}{-\frac{1}{8}}-12\right)\times 3$$

Multiply 13,4 and 2 to get 26,8.

$$\left(\frac{\frac{273}{10}-26,8}{-\frac{1}{8}}-12\right)\times 3$$

Convert decimal number 26,8 to fraction \frac{268}{10}. Reduce the fraction \frac{268}{10} to lowest terms by extracting and canceling out 2.

$$\left(\frac{\frac{273}{10}-\frac{134}{5}}{-\frac{1}{8}}-12\right)\times 3$$

Least common multiple of 10 and 5 is 10. Convert \frac{273}{10} and \frac{134}{5} to fractions with denominator 10.

$$\left(\frac{\frac{273}{10}-\frac{268}{10}}{-\frac{1}{8}}-12\right)\times 3$$

Since \frac{273}{10} and \frac{268}{10} have the same denominator, subtract them by subtracting their numerators.

$$\left(\frac{\frac{273-268}{10}}{-\frac{1}{8}}-12\right)\times 3$$

Subtract 268 from 273 to get 5.

$$\left(\frac{\frac{5}{10}}{-\frac{1}{8}}-12\right)\times 3$$

Reduce the fraction \frac{5}{10} to lowest terms by extracting and canceling out 5.

$$\left(\frac{\frac{1}{2}}{-\frac{1}{8}}-12\right)\times 3$$

Divide \frac{1}{2} by -\frac{1}{8} by multiplying \frac{1}{2} by the reciprocal of -\frac{1}{8}.

$$\left(\frac{1}{2}\left(-8\right)-12\right)\times 3$$

Multiply \frac{1}{2} and -8 to get \frac{-8}{2}.

$$\left(\frac{-8}{2}-12\right)\times 3$$

Divide -8 by 2 to get -4.

$$\left(-4-12\right)\times 3$$

Subtract 12 from -4 to get -16.

$$-16\times 3$$

Multiply -16 and 3 to get -48.

$$-48$$

Factor

$$-48$$