Solve ((22-20)^2+(1-0)^2+(42-36)^2+(10-8))

$$( ( 22 - 20 ) ^ { 2 } + ( 1 - 0 ) ^ { 2 } + ( 42 - 36 ) ^ { 2 } + ( 10 - 8 ) )$$

Evaluate

$$43$$

Solution Steps

Subtract 20 from 22 to get 2.

$$2^{2}+\left(1-0\right)^{2}+\left(42-36\right)^{2}+10-8$$

Calculate 2 to the power of 2 and get 4.

$$4+\left(1-0\right)^{2}+\left(42-36\right)^{2}+10-8$$

Subtract 0 from 1 to get 1.

$$4+1^{2}+\left(42-36\right)^{2}+10-8$$

Calculate 1 to the power of 2 and get 1.

$$4+1+\left(42-36\right)^{2}+10-8$$

Add 4 and 1 to get 5.

$$5+\left(42-36\right)^{2}+10-8$$

Subtract 36 from 42 to get 6.

$$5+6^{2}+10-8$$

Calculate 6 to the power of 2 and get 36.

$$5+36+10-8$$

Add 5 and 36 to get 41.

$$41+10-8$$

Add 41 and 10 to get 51.

$$51-8$$

Subtract 8 from 51 to get 43.

$$43$$

Factor

$$43$$