Solve ((2-1/4)*(3-1/2))^2-sqrt{9}

$$( ( 2 - \frac { 1 } { 4 } ) \cdot ( 3 - \frac { 1 } { 2 } ) ) ^ { 2 } - \sqrt { 9 }$$

Evaluate

$$\frac{1033}{64}=16.140625$$

Solution Steps

Subtract \frac{1}{4} from 2 to get \frac{7}{4}.

$$\left(\frac{7}{4}\left(3-\frac{1}{2}\right)\right)^{2}-\sqrt{9}$$

Subtract \frac{1}{2} from 3 to get \frac{5}{2}.

$$\left(\frac{7}{4}\times \frac{5}{2}\right)^{2}-\sqrt{9}$$

Multiply \frac{7}{4} and \frac{5}{2} to get \frac{35}{8}.

$$\left(\frac{35}{8}\right)^{2}-\sqrt{9}$$

Calculate \frac{35}{8} to the power of 2 and get \frac{1225}{64}.

$$\frac{1225}{64}-\sqrt{9}$$

Calculate the square root of 9 and get 3.

$$\frac{1225}{64}-3$$

Subtract 3 from \frac{1225}{64} to get \frac{1033}{64}.

$$\frac{1033}{64}$$

Factor

$$\frac{1033}{2 ^ {6}} = 16\frac{9}{64} = 16.140625$$