Solve ((0*x)+(1*5)+(2*6)+(3*3)+(4*2))div(x+5+6+3+2)=2

$$( ( 0 \times x ) + ( 1 \times 5 ) + ( 2 \times 6 ) + ( 3 \times 3 ) + ( 4 \times 2 ) ) \div ( x + 5 + 6 + 3 + 2 ) = 2$$

Solve for x

$$x=1$$

Steps for Solving Linear Equation

Variable x cannot be equal to -16 since division by zero is not defined. Multiply both sides of the equation by x+16.

$$0x+1\times 5+2\times 6+3\times 3+4\times 2=2\left(x+16\right)$$

Do the multiplications.

$$0x+5+12+9+8=2\left(x+16\right)$$

Anything times zero gives zero.

$$0+5+12+9+8=2\left(x+16\right)$$

Add 0 and 5 to get 5.

$$5+12+9+8=2\left(x+16\right)$$

Add 5 and 12 to get 17.

$$17+9+8=2\left(x+16\right)$$

Add 17 and 9 to get 26.

$$26+8=2\left(x+16\right)$$

Add 26 and 8 to get 34.

$$34=2\left(x+16\right)$$

Use the distributive property to multiply 2 by x+16.

$$34=2x+32$$

Swap sides so that all variable terms are on the left hand side.

$$2x+32=34$$

Subtract 32 from both sides.

$$2x=34-32$$

Subtract 32 from 34 to get 2.

$$2x=2$$

Divide both sides by 2.

$$x=\frac{2}{2}$$

Divide 2 by 2 to get 1.

$$x=1$$