Solve ((-10)-(-10))^2+(0-4)^2+(5-3)^2

$$( ( - 10 ) - ( - 10 ) ) ^ { 2 } + ( 0 - 4 ) ^ { 2 } + ( 5 - 3 ) ^ { 2 }$$

Evaluate

$$20$$

Solution Steps

The opposite of -10 is 10.

$$\left(-10+10\right)^{2}+\left(0-4\right)^{2}+\left(5-3\right)^{2}$$

Add -10 and 10 to get 0.

$$0^{2}+\left(0-4\right)^{2}+\left(5-3\right)^{2}$$

Calculate 0 to the power of 2 and get 0.

$$0+\left(0-4\right)^{2}+\left(5-3\right)^{2}$$

Subtract 4 from 0 to get -4.

$$0+\left(-4\right)^{2}+\left(5-3\right)^{2}$$

Calculate -4 to the power of 2 and get 16.

$$0+16+\left(5-3\right)^{2}$$

Add 0 and 16 to get 16.

$$16+\left(5-3\right)^{2}$$

Subtract 3 from 5 to get 2.

$$16+2^{2}$$

Calculate 2 to the power of 2 and get 4.

$$16+4$$

Add 16 and 4 to get 20.

$$20$$

Factor

$$2^{2}\times 5$$