Solve (x^2*1.2)*y=x^2*(1.44*y)

$$( { x }^{ 2 } \times 1.2) \times y= { x }^{ 2 } \times (1.44 \times y)$$

Solve for x (complex solution)

$$\left\{\begin{matrix}\\x=0\text{, }&\text{unconditionally}\\x\in \mathrm{C}\text{, }&y=0\end{matrix}\right.$$

Steps by Finding Square Root

Subtract x^{2}\times 1.44y from both sides.

$$x^{2}\times 1.2y-x^{2}\times 1.44y=0$$

Combine x^{2}\times 1.2y and -x^{2}\times 1.44y to get -0.24x^{2}y.

$$-0.24x^{2}y=0$$

Dividing by -0.24y undoes the multiplication by -0.24y.

$$x^{2}=\frac{0}{-\frac{6y}{25}}$$

Divide 0 by -0.24y.

$$x^{2}=0$$

Take the square root of both sides of the equation.

$$x=0 x=0$$

The equation is now solved. Solutions are the same.

$$x=0$$

Steps Using the Quadratic Formula

Subtract x^{2}\times 1.44y from both sides.

$$x^{2}\times 1.2y-x^{2}\times 1.44y=0$$

Combine x^{2}\times 1.2y and -x^{2}\times 1.44y to get -0.24x^{2}y.

$$-0.24x^{2}y=0$$

Quadratic equations like this one, with an x^{2} term but no x term, can still be solved using the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}, once they are put in standard form: ax^{2}+bx+c=0.

$$\left(-\frac{6y}{25}\right)x^{2}=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute -0.24y for a, 0 for b, and 0 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}}}{2\left(-\frac{6y}{25}\right)}$$

Take the square root of 0^{2}.

$$x=\frac{0±0}{2\left(-\frac{6y}{25}\right)}$$

Multiply 2 times -0.24y.

$$x=\frac{0}{-\frac{12y}{25}}$$

Divide 0 by -\frac{12y}{25}.

$$x=0$$

Solve for y (complex solution)

$$\left\{\begin{matrix}\\y=0\text{, }&\text{unconditionally}\\y\in \mathrm{C}\text{, }&x=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Subtract x^{2}\times 1.44y from both sides.

$$x^{2}\times 1.2y-x^{2}\times 1.44y=0$$

Combine x^{2}\times 1.2y and -x^{2}\times 1.44y to get -0.24x^{2}y.

$$-0.24x^{2}y=0$$

The equation is in standard form.

$$\left(-\frac{6x^{2}}{25}\right)y=0$$

Divide 0 by -0.24x^{2}.

$$y=0$$

Solve for y

$$\left\{\begin{matrix}\\y=0\text{, }&\text{unconditionally}\\y\in \mathrm{R}\text{, }&x=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Subtract x^{2}\times 1.44y from both sides.

$$x^{2}\times 1.2y-x^{2}\times 1.44y=0$$

Combine x^{2}\times 1.2y and -x^{2}\times 1.44y to get -0.24x^{2}y.

$$-0.24x^{2}y=0$$

The equation is in standard form.

$$\left(-\frac{6x^{2}}{25}\right)y=0$$

Divide 0 by -0.24x^{2}.

$$y=0$$

Solve for x

$$\left\{\begin{matrix}\\x=0\text{, }&\text{unconditionally}\\x\in \mathrm{R}\text{, }&y=0\end{matrix}\right.$$