Solve (69^2+1)+11/4

$$( { 69 }^{ 2 } +1)+ 1 \frac { 1 } { 4 }$$

Evaluate

$$\frac{19053}{4}=4763.25$$

Solution Steps

Calculate 69 to the power of 2 and get 4761.

$$4761+1+\frac{1\times 4+1}{4}$$

Add 4761 and 1 to get 4762.

$$4762+\frac{1\times 4+1}{4}$$

Multiply 1 and 4 to get 4.

$$4762+\frac{4+1}{4}$$

Add 4 and 1 to get 5.

$$4762+\frac{5}{4}$$

Convert 4762 to fraction \frac{19048}{4}.

$$\frac{19048}{4}+\frac{5}{4}$$

Since \frac{19048}{4} and \frac{5}{4} have the same denominator, add them by adding their numerators.

$$\frac{19048+5}{4}$$

Add 19048 and 5 to get 19053.

$$\frac{19053}{4}$$

Factor

$$\frac{3 ^ {2} \cdot 29 \cdot 73}{2 ^ {2}} = 4763\frac{1}{4} = 4763.25$$