Solve (64.001^3+64.001)-(4^3+4)

$$( { 64.001 }^{ 3 } +64.001)-( { 4 }^{ 3 } +4)$$

Evaluate

$$262152.289192001$$

Solution Steps

Calculate 64.001 to the power of 3 and get 262156.288192001.

$$262156.288192001+64.001-\left(4^{3}+4\right)$$

Add 262156.288192001 and 64.001 to get 262220.289192001.

$$262220.289192001-\left(4^{3}+4\right)$$

Calculate 4 to the power of 3 and get 64.

$$262220.289192001-\left(64+4\right)$$

Add 64 and 4 to get 68.

$$262220.289192001-68$$

Subtract 68 from 262220.289192001 to get 262152.289192001.

$$262152.289192001$$

Factor

$$\frac{13 \cdot 29 \cdot 2069 \cdot 5821 \cdot 57737}{2 ^ {9} \cdot 5 ^ {9}} = 262152\frac{289192001}{1000000000} = 262152.289192001$$