Solve (6.8^2+6.8^2)-(2*6.8*6.8)cos(72)

$$( { 6.8 }^{ 2 } + { 6.8 }^{ 2 } )-(2 \times 6.8 \times 6.8) \cos ( 72 )$$

Evaluate

$$63.902108360204859824$$

Solution Steps

Evaluate trigonometric functions in the problem

$${({(6.8)} ^ {2} + {(6.8)} ^ {2})} - {(2 \cdot 6.8 \cdot 6.8)} 0.30901699437494745$$

Calculate 6.8 to the power of 2 and get 46.24.

$$46.24+6.8^{2}-2\times 6.8\times 6.8\times 0.30901699437494745$$

Calculate 6.8 to the power of 2 and get 46.24.

$$46.24+46.24-2\times 6.8\times 6.8\times 0.30901699437494745$$

Add 46.24 and 46.24 to get 92.48.

$$92.48-2\times 6.8\times 6.8\times 0.30901699437494745$$

Multiply 2 and 6.8 to get 13.6.

$$92.48-13.6\times 6.8\times 0.30901699437494745$$

Multiply 13.6 and 6.8 to get 92.48.

$$92.48-92.48\times 0.30901699437494745$$

Multiply 92.48 and 0.30901699437494745 to get 28.577891639795140176.

$$92.48-28.577891639795140176$$

Subtract 28.577891639795140176 from 92.48 to get 63.902108360204859824.

$$63.902108360204859824$$

Factor

$$\frac{13819660112501051 \cdot 17 ^ {2}}{2 ^ {14} \cdot 5 ^ {18}} = 63\frac{56381772512803840}{62500000000000000} = 63.90210836020486$$