Solve (6^-1+4^-1)-1^2

$$( { 6 }^{ -1 } + { 4 }^{ -1 } ) { -1 }^{ 2 }$$

Evaluate

$$\frac{5}{12}\approx 0.416666667$$

Solution Steps

Calculate 6 to the power of -1 and get \frac{1}{6}.

$$\left(\frac{1}{6}+4^{-1}\right)\left(-1\right)^{2}$$

Calculate 4 to the power of -1 and get \frac{1}{4}.

$$\left(\frac{1}{6}+\frac{1}{4}\right)\left(-1\right)^{2}$$

Add \frac{1}{6} and \frac{1}{4} to get \frac{5}{12}.

$$\frac{5}{12}\left(-1\right)^{2}$$

Calculate -1 to the power of 2 and get 1.

$$\frac{5}{12}\times 1$$

Multiply \frac{5}{12} and 1 to get \frac{5}{12}.

$$\frac{5}{12}$$

Factor

$$\frac{5}{2 ^ {2} \cdot 3} = 0.4166666666666667$$