Solve (2.99^3+5(2.99^2)-2(2.99))div(2.99^2-2(2.99))

$$( { 2.99 }^{ 3 } +5( { 2.99 }^{ 2 } )-2(2.99)) \div ( { 2.99 }^{ 2 } -2(2.99))$$

Evaluate

$$\frac{72967}{3300}\approx 22.111212121$$

Solution Steps

Calculate 2.99 to the power of 3 and get 26.730899.

$$\frac{26.730899+5\times 2.99^{2}-2\times 2.99}{2.99^{2}-2\times 2.99}$$

Calculate 2.99 to the power of 2 and get 8.9401.

$$\frac{26.730899+5\times 8.9401-2\times 2.99}{2.99^{2}-2\times 2.99}$$

Multiply 5 and 8.9401 to get 44.7005.

$$\frac{26.730899+44.7005-2\times 2.99}{2.99^{2}-2\times 2.99}$$

Add 26.730899 and 44.7005 to get 71.431399.

$$\frac{71.431399-2\times 2.99}{2.99^{2}-2\times 2.99}$$

Multiply 2 and 2.99 to get 5.98.

$$\frac{71.431399-5.98}{2.99^{2}-2\times 2.99}$$

Subtract 5.98 from 71.431399 to get 65.451399.

$$\frac{65.451399}{2.99^{2}-2\times 2.99}$$

Calculate 2.99 to the power of 2 and get 8.9401.

$$\frac{65.451399}{8.9401-2\times 2.99}$$

Multiply 2 and 2.99 to get 5.98.

$$\frac{65.451399}{8.9401-5.98}$$

Subtract 5.98 from 8.9401 to get 2.9601.

$$\frac{65.451399}{2.9601}$$

Expand \frac{65.451399}{2.9601} by multiplying both numerator and the denominator by 1000000.

$$\frac{65451399}{2960100}$$

Reduce the fraction \frac{65451399}{2960100} to lowest terms by extracting and canceling out 897.

$$\frac{72967}{3300}$$

Factor

$$\frac{131 \cdot 557}{3 \cdot 11 \cdot 2 ^ {2} \cdot 5 ^ {2}} = 22\frac{367}{3300} = 22.11121212121212$$