Solve (2^8+2^7)div2^5+2^2

$$( { 2 }^{ 8 } + { 2 }^{ 7 } ) \div { 2 }^{ 5 } + { 2 }^{ 2 }$$

Evaluate

$$16$$

Solution Steps

Calculate 2 to the power of 8 and get 256.

$$\frac{256+2^{7}}{2^{5}}+2^{2}$$

Calculate 2 to the power of 7 and get 128.

$$\frac{256+128}{2^{5}}+2^{2}$$

Add 256 and 128 to get 384.

$$\frac{384}{2^{5}}+2^{2}$$

Calculate 2 to the power of 5 and get 32.

$$\frac{384}{32}+2^{2}$$

Divide 384 by 32 to get 12.

$$12+2^{2}$$

Calculate 2 to the power of 2 and get 4.

$$12+4$$

Add 12 and 4 to get 16.

$$16$$

Factor

$$2^{4}$$