Solve (2^2+6^2-8^2)div2*2=

$$( { 2 }^{ 2 } + { 6 }^{ 2 } - { 8 }^{ 2 } ) \div 2 \times 2=$$

Evaluate

$$-24$$

Solution Steps

Calculate 2 to the power of 2 and get 4.

$$\frac{4+6^{2}-8^{2}}{2}\times 2$$

Calculate 6 to the power of 2 and get 36.

$$\frac{4+36-8^{2}}{2}\times 2$$

Add 4 and 36 to get 40.

$$\frac{40-8^{2}}{2}\times 2$$

Calculate 8 to the power of 2 and get 64.

$$\frac{40-64}{2}\times 2$$

Subtract 64 from 40 to get -24.

$$\frac{-24}{2}\times 2$$

Divide -24 by 2 to get -12.

$$-12\times 2$$

Multiply -12 and 2 to get -24.

$$-24$$

Factor

$$-24$$