Solve (2^2+1/9)(3-1/3)

$$( { 2 }^{ 2 } + \frac{ 1 }{ 9 } )(3- \frac{ 1 }{ 3 } )$$

Evaluate

$$\frac{296}{27}\approx 10.962962963$$

Solution Steps

Calculate 2 to the power of 2 and get 4.

$$\left(4+\frac{1}{9}\right)\left(3-\frac{1}{3}\right)$$

Convert 4 to fraction \frac{36}{9}.

$$\left(\frac{36}{9}+\frac{1}{9}\right)\left(3-\frac{1}{3}\right)$$

Since \frac{36}{9} and \frac{1}{9} have the same denominator, add them by adding their numerators.

$$\frac{36+1}{9}\left(3-\frac{1}{3}\right)$$

Add 36 and 1 to get 37.

$$\frac{37}{9}\left(3-\frac{1}{3}\right)$$

Convert 3 to fraction \frac{9}{3}.

$$\frac{37}{9}\left(\frac{9}{3}-\frac{1}{3}\right)$$

Since \frac{9}{3} and \frac{1}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{37}{9}\times \frac{9-1}{3}$$

Subtract 1 from 9 to get 8.

$$\frac{37}{9}\times \frac{8}{3}$$

Multiply \frac{37}{9} times \frac{8}{3} by multiplying numerator times numerator and denominator times denominator.

$$\frac{37\times 8}{9\times 3}$$

Do the multiplications in the fraction \frac{37\times 8}{9\times 3}.

$$\frac{296}{27}$$

Factor

$$\frac{2 ^ {3} \cdot 37}{3 ^ {3}} = 10\frac{26}{27} = 10.962962962962964$$