Solve (104^2+63^2-25^2)div(2*104*63)=

$$( { 104 }^{ 2 } + { 63 }^{ 2 } - { 25 }^{ 2 } ) \div (2 \times 104 \times 63)=$$

Evaluate

$$\frac{295}{273}\approx 1.080586081$$

Solution Steps

Calculate 104 to the power of 2 and get 10816.

$$\frac{10816+63^{2}-25^{2}}{2\times 104\times 63}$$

Calculate 63 to the power of 2 and get 3969.

$$\frac{10816+3969-25^{2}}{2\times 104\times 63}$$

Add 10816 and 3969 to get 14785.

$$\frac{14785-25^{2}}{2\times 104\times 63}$$

Calculate 25 to the power of 2 and get 625.

$$\frac{14785-625}{2\times 104\times 63}$$

Subtract 625 from 14785 to get 14160.

$$\frac{14160}{2\times 104\times 63}$$

Multiply 2 and 104 to get 208.

$$\frac{14160}{208\times 63}$$

Multiply 208 and 63 to get 13104.

$$\frac{14160}{13104}$$

Reduce the fraction \frac{14160}{13104} to lowest terms by extracting and canceling out 48.

$$\frac{295}{273}$$

Factor

$$\frac{5 \cdot 59}{3 \cdot 7 \cdot 13} = 1\frac{22}{273} = 1.0805860805860805$$