Solve (left(2.01-2.00right)^2+left(2.04-2.00right)^2+left(1.98-2.00right)^2+left(1.98-2.00right)^2)*0.25

$$( { \left(2.01-2.00 \right) }^{ 2 } + { \left(2.04-2.00 \right) }^{ 2 } + { \left(1.98-2.00 \right) }^{ 2 } + { \left(1.98-2.00 \right) }^{ 2 } ) \times 0.25$$

Evaluate

$$0.000625$$

Solution Steps

Subtract 2 from 2.01 to get 0.01.

$$\left(0.01^{2}+\left(2.04-2\right)^{2}+\left(1.98-2\right)^{2}+\left(1.98-2\right)^{2}\right)\times 0.25$$

Calculate 0.01 to the power of 2 and get 0.0001.

$$\left(0.0001+\left(2.04-2\right)^{2}+\left(1.98-2\right)^{2}+\left(1.98-2\right)^{2}\right)\times 0.25$$

Subtract 2 from 2.04 to get 0.04.

$$\left(0.0001+0.04^{2}+\left(1.98-2\right)^{2}+\left(1.98-2\right)^{2}\right)\times 0.25$$

Calculate 0.04 to the power of 2 and get 0.0016.

$$\left(0.0001+0.0016+\left(1.98-2\right)^{2}+\left(1.98-2\right)^{2}\right)\times 0.25$$

Add 0.0001 and 0.0016 to get 0.0017.

$$\left(0.0017+\left(1.98-2\right)^{2}+\left(1.98-2\right)^{2}\right)\times 0.25$$

Subtract 2 from 1.98 to get -0.02.

$$\left(0.0017+\left(-0.02\right)^{2}+\left(1.98-2\right)^{2}\right)\times 0.25$$

Calculate -0.02 to the power of 2 and get 0.0004.

$$\left(0.0017+0.0004+\left(1.98-2\right)^{2}\right)\times 0.25$$

Add 0.0017 and 0.0004 to get 0.0021.

$$\left(0.0021+\left(1.98-2\right)^{2}\right)\times 0.25$$

Subtract 2 from 1.98 to get -0.02.

$$\left(0.0021+\left(-0.02\right)^{2}\right)\times 0.25$$

Calculate -0.02 to the power of 2 and get 0.0004.

$$\left(0.0021+0.0004\right)\times 0.25$$

Add 0.0021 and 0.0004 to get 0.0025.

$$0.0025\times 0.25$$

Multiply 0.0025 and 0.25 to get 0.000625.

$$0.000625$$

Factor

$$\frac{1}{2 ^ {6} \cdot 5 ^ {2}} = 0.000625$$