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\left(\sqrt{8}\right)^{2}-\left(\sqrt{10}\right)^{2}
Multiplication can be transformed into difference of squares using the rule: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.
8-\left(\sqrt{10}\right)^{2}
The square of \sqrt{8} is 8.
8-10
The square of \sqrt{10} is 10.
-2
Subtract 10 from 8 to get -2.