Evaluate
43-12\sqrt{7}\approx 11.250984267
Expand
43-12\sqrt{7}
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\left(\sqrt{7}\right)^{2}-12\sqrt{7}+36
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(\sqrt{7}-6\right)^{2}.
7-12\sqrt{7}+36
The square of \sqrt{7} is 7.
43-12\sqrt{7}
Add 7 and 36 to get 43.
\left(\sqrt{7}\right)^{2}-12\sqrt{7}+36
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(\sqrt{7}-6\right)^{2}.
7-12\sqrt{7}+36
The square of \sqrt{7} is 7.
43-12\sqrt{7}
Add 7 and 36 to get 43.
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