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\left(\sqrt{7}\right)^{2}+2\sqrt{7}-3\sqrt{7}-6
Apply the distributive property by multiplying each term of \sqrt{7}-3 by each term of \sqrt{7}+2.
7+2\sqrt{7}-3\sqrt{7}-6
The square of \sqrt{7} is 7.
7-\sqrt{7}-6
Combine 2\sqrt{7} and -3\sqrt{7} to get -\sqrt{7}.
1-\sqrt{7}
Subtract 6 from 7 to get 1.