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2\sqrt{7}x+7
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2\sqrt{7}x+7
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\left(\sqrt{7}\right)^{2}+2\sqrt{7}x+x^{2}-x^{2}
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(\sqrt{7}+x\right)^{2}.
7+2\sqrt{7}x+x^{2}-x^{2}
The square of \sqrt{7} is 7.
7+2\sqrt{7}x
Combine x^{2} and -x^{2} to get 0.
\left(\sqrt{7}\right)^{2}+2\sqrt{7}x+x^{2}-x^{2}
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(\sqrt{7}+x\right)^{2}.
7+2\sqrt{7}x+x^{2}-x^{2}
The square of \sqrt{7} is 7.
7+2\sqrt{7}x
Combine x^{2} and -x^{2} to get 0.
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