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\left(\sqrt{7}\right)^{2}-\left(4\sqrt{3}\right)^{2}
Multiplication can be transformed into difference of squares using the rule: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.
7-\left(4\sqrt{3}\right)^{2}
The square of \sqrt{7} is 7.
7-4^{2}\left(\sqrt{3}\right)^{2}
Expand \left(4\sqrt{3}\right)^{2}.
7-16\left(\sqrt{3}\right)^{2}
Calculate 4 to the power of 2 and get 16.
7-16\times 3
The square of \sqrt{3} is 3.
7-48
Multiply 16 and 3 to get 48.
-41
Subtract 48 from 7 to get -41.