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\left(\sqrt{7}\right)^{2}-\left(\sqrt{6}\right)^{2}
Multiplication can be transformed into difference of squares using the rule: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.
7-\left(\sqrt{6}\right)^{2}
The square of \sqrt{7} is 7.
7-6
The square of \sqrt{6} is 6.
1
Subtract 6 from 7 to get 1.