Solve (sqrt{63}-sqrt{28})-sqrt{7}

$$( \sqrt { 63 } - \sqrt { 28 } ) - \sqrt { 7 }$$

Evaluate

$$0$$

Solution Steps

Factor 63=3^{2}\times 7. Rewrite the square root of the product \sqrt{3^{2}\times 7} as the product of square roots \sqrt{3^{2}}\sqrt{7}. Take the square root of 3^{2}.

$$3\sqrt{7}-\sqrt{28}-\sqrt{7}$$

Factor 28=2^{2}\times 7. Rewrite the square root of the product \sqrt{2^{2}\times 7} as the product of square roots \sqrt{2^{2}}\sqrt{7}. Take the square root of 2^{2}.

$$3\sqrt{7}-2\sqrt{7}-\sqrt{7}$$

Combine 3\sqrt{7} and -2\sqrt{7} to get \sqrt{7}.

$$\sqrt{7}-\sqrt{7}$$

Combine \sqrt{7} and -\sqrt{7} to get 0.

$$0$$

Factor

$$0$$