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\left(\sqrt{6}\right)^{2}+3\sqrt{6}+\sqrt{6}+3
Apply the distributive property by multiplying each term of \sqrt{6}+1 by each term of \sqrt{6}+3.
6+3\sqrt{6}+\sqrt{6}+3
The square of \sqrt{6} is 6.
6+4\sqrt{6}+3
Combine 3\sqrt{6} and \sqrt{6} to get 4\sqrt{6}.
9+4\sqrt{6}
Add 6 and 3 to get 9.