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\left(\sqrt{5}-\sqrt{2}\right)^{2}
Multiply \sqrt{5}-\sqrt{2} and \sqrt{5}-\sqrt{2} to get \left(\sqrt{5}-\sqrt{2}\right)^{2}.
\left(\sqrt{5}\right)^{2}-2\sqrt{5}\sqrt{2}+\left(\sqrt{2}\right)^{2}
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(\sqrt{5}-\sqrt{2}\right)^{2}.
5-2\sqrt{5}\sqrt{2}+\left(\sqrt{2}\right)^{2}
The square of \sqrt{5} is 5.
5-2\sqrt{10}+\left(\sqrt{2}\right)^{2}
To multiply \sqrt{5} and \sqrt{2}, multiply the numbers under the square root.
5-2\sqrt{10}+2
The square of \sqrt{2} is 2.
7-2\sqrt{10}
Add 5 and 2 to get 7.