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\left(\frac{\sqrt{\frac{245+11}{49}}}{\sqrt[3]{\frac{216}{343}}}+\sqrt{\frac{1\times 81+40}{81}}\right)\sqrt[3]{\frac{5\times 125+104}{125}}
Multiply 5 and 49 to get 245.
\left(\frac{\sqrt{\frac{256}{49}}}{\sqrt[3]{\frac{216}{343}}}+\sqrt{\frac{1\times 81+40}{81}}\right)\sqrt[3]{\frac{5\times 125+104}{125}}
Add 245 and 11 to get 256.
\left(\frac{\frac{16}{7}}{\sqrt[3]{\frac{216}{343}}}+\sqrt{\frac{1\times 81+40}{81}}\right)\sqrt[3]{\frac{5\times 125+104}{125}}
Rewrite the square root of the division \frac{256}{49} as the division of square roots \frac{\sqrt{256}}{\sqrt{49}}. Take the square root of both numerator and denominator.
\left(\frac{\frac{16}{7}}{\frac{6}{7}}+\sqrt{\frac{1\times 81+40}{81}}\right)\sqrt[3]{\frac{5\times 125+104}{125}}
Calculate \sqrt[3]{\frac{216}{343}} and get \frac{6}{7}.
\left(\frac{16}{7}\times \frac{7}{6}+\sqrt{\frac{1\times 81+40}{81}}\right)\sqrt[3]{\frac{5\times 125+104}{125}}
Divide \frac{16}{7} by \frac{6}{7} by multiplying \frac{16}{7} by the reciprocal of \frac{6}{7}.
\left(\frac{8}{3}+\sqrt{\frac{1\times 81+40}{81}}\right)\sqrt[3]{\frac{5\times 125+104}{125}}
Multiply \frac{16}{7} and \frac{7}{6} to get \frac{8}{3}.
\left(\frac{8}{3}+\sqrt{\frac{81+40}{81}}\right)\sqrt[3]{\frac{5\times 125+104}{125}}
Multiply 1 and 81 to get 81.
\left(\frac{8}{3}+\sqrt{\frac{121}{81}}\right)\sqrt[3]{\frac{5\times 125+104}{125}}
Add 81 and 40 to get 121.
\left(\frac{8}{3}+\frac{11}{9}\right)\sqrt[3]{\frac{5\times 125+104}{125}}
Rewrite the square root of the division \frac{121}{81} as the division of square roots \frac{\sqrt{121}}{\sqrt{81}}. Take the square root of both numerator and denominator.
\frac{35}{9}\sqrt[3]{\frac{5\times 125+104}{125}}
Add \frac{8}{3} and \frac{11}{9} to get \frac{35}{9}.
\frac{35}{9}\sqrt[3]{\frac{625+104}{125}}
Multiply 5 and 125 to get 625.
\frac{35}{9}\sqrt[3]{\frac{729}{125}}
Add 625 and 104 to get 729.
\frac{35}{9}\times \frac{9}{5}
Calculate \sqrt[3]{\frac{729}{125}} and get \frac{9}{5}.
7
Multiply \frac{35}{9} and \frac{9}{5} to get 7.