Solve (sqrt{36}+4^2)-(3^2-5^2)

$$( \sqrt { 36 } + 4 ^ { 2 } ) - ( 3 ^ { 2 } - 5 ^ { 2 } )$$

Evaluate

$$38$$

Solution Steps

Calculate the square root of 36 and get 6.

$$6+4^{2}-\left(3^{2}-5^{2}\right)$$

Calculate 4 to the power of 2 and get 16.

$$6+16-\left(3^{2}-5^{2}\right)$$

Add 6 and 16 to get 22.

$$22-\left(3^{2}-5^{2}\right)$$

Calculate 3 to the power of 2 and get 9.

$$22-\left(9-5^{2}\right)$$

Calculate 5 to the power of 2 and get 25.

$$22-\left(9-25\right)$$

Subtract 25 from 9 to get -16.

$$22-\left(-16\right)$$

The opposite of -16 is 16.

$$22+16$$

Add 22 and 16 to get 38.

$$38$$

Factor

$$2\times 19$$