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\left(\sqrt{3}\right)^{2}x^{2}-10\sqrt{3}x+25
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(\sqrt{3}x-5\right)^{2}.
3x^{2}-10\sqrt{3}x+25
The square of \sqrt{3} is 3.
\left(\sqrt{3}\right)^{2}x^{2}-10\sqrt{3}x+25
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(\sqrt{3}x-5\right)^{2}.
3x^{2}-10\sqrt{3}x+25
The square of \sqrt{3} is 3.