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\left(\sqrt{3}\right)^{2}x^{2}+2\sqrt{3}x\sqrt{3}+\left(\sqrt{3}\right)^{2}
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(\sqrt{3}x+\sqrt{3}\right)^{2}.
\left(\sqrt{3}\right)^{2}x^{2}+2\times 3x+\left(\sqrt{3}\right)^{2}
Multiply \sqrt{3} and \sqrt{3} to get 3.
3x^{2}+2\times 3x+\left(\sqrt{3}\right)^{2}
The square of \sqrt{3} is 3.
3x^{2}+6x+\left(\sqrt{3}\right)^{2}
Multiply 2 and 3 to get 6.
3x^{2}+6x+3
The square of \sqrt{3} is 3.
\left(\sqrt{3}\right)^{2}x^{2}+2\sqrt{3}x\sqrt{3}+\left(\sqrt{3}\right)^{2}
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(\sqrt{3}x+\sqrt{3}\right)^{2}.
\left(\sqrt{3}\right)^{2}x^{2}+2\times 3x+\left(\sqrt{3}\right)^{2}
Multiply \sqrt{3} and \sqrt{3} to get 3.
3x^{2}+2\times 3x+\left(\sqrt{3}\right)^{2}
The square of \sqrt{3} is 3.
3x^{2}+6x+\left(\sqrt{3}\right)^{2}
Multiply 2 and 3 to get 6.
3x^{2}+6x+3
The square of \sqrt{3} is 3.