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-\left(\sqrt{3}\right)^{2}-2i\sqrt{3}+1
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(i\sqrt{3}-1\right)^{2}.
-3-2i\sqrt{3}+1
The square of \sqrt{3} is 3.
-2-2i\sqrt{3}
Add -3 and 1 to get -2.
-\left(\sqrt{3}\right)^{2}-2i\sqrt{3}+1
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(i\sqrt{3}-1\right)^{2}.
-3-2i\sqrt{3}+1
The square of \sqrt{3} is 3.
-2-2i\sqrt{3}
Add -3 and 1 to get -2.