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\left(\sqrt{3}\right)^{2}-5\sqrt{3}-8\sqrt{3}+40
Apply the distributive property by multiplying each term of \sqrt{3}-8 by each term of \sqrt{3}-5.
3-5\sqrt{3}-8\sqrt{3}+40
The square of \sqrt{3} is 3.
3-13\sqrt{3}+40
Combine -5\sqrt{3} and -8\sqrt{3} to get -13\sqrt{3}.
43-13\sqrt{3}
Add 3 and 40 to get 43.