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\left(\sqrt{3}\right)^{2}-8\sqrt{3}+16
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(\sqrt{3}-4\right)^{2}.
3-8\sqrt{3}+16
The square of \sqrt{3} is 3.
19-8\sqrt{3}
Add 3 and 16 to get 19.
\left(\sqrt{3}\right)^{2}-8\sqrt{3}+16
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(\sqrt{3}-4\right)^{2}.
3-8\sqrt{3}+16
The square of \sqrt{3} is 3.
19-8\sqrt{3}
Add 3 and 16 to get 19.