Evaluate
\frac{13}{4}-\sqrt{3}\approx 1.517949192
Expand
\frac{13}{4} - \sqrt{3} = 1.517949192
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\left(\sqrt{3}\right)^{2}-\sqrt{3}+\frac{1}{4}
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(\sqrt{3}-\frac{1}{2}\right)^{2}.
3-\sqrt{3}+\frac{1}{4}
The square of \sqrt{3} is 3.
\frac{13}{4}-\sqrt{3}
Add 3 and \frac{1}{4} to get \frac{13}{4}.
\left(\sqrt{3}\right)^{2}-\sqrt{3}+\frac{1}{4}
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(\sqrt{3}-\frac{1}{2}\right)^{2}.
3-\sqrt{3}+\frac{1}{4}
The square of \sqrt{3} is 3.
\frac{13}{4}-\sqrt{3}
Add 3 and \frac{1}{4} to get \frac{13}{4}.
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