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\frac{\sqrt{3}\sqrt{2}}{-\left(\sqrt{2}\right)^{2}}
Rationalize the denominator of \frac{\sqrt{3}}{-\sqrt{2}} by multiplying numerator and denominator by \sqrt{2}.
\frac{\sqrt{3}\sqrt{2}}{-2}
The square of \sqrt{2} is 2.
\frac{\sqrt{6}}{-2}
To multiply \sqrt{3} and \sqrt{2}, multiply the numbers under the square root.