Evaluate
2+2\sqrt{3}i\approx 2+3.464101615i
Real Part
2
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\left(\sqrt{3}+i\right)^{2}
Add 1 and 1 to get 2.
\left(\sqrt{3}\right)^{2}+2i\sqrt{3}-1
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(\sqrt{3}+i\right)^{2}.
3+2i\sqrt{3}-1
The square of \sqrt{3} is 3.
2+2i\sqrt{3}
Subtract 1 from 3 to get 2.
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