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2\left(\sqrt{3}\right)^{2}+2\sqrt{3}+8\sqrt{3}+8
Apply the distributive property by multiplying each term of \sqrt{3}+4 by each term of 2\sqrt{3}+2.
2\times 3+2\sqrt{3}+8\sqrt{3}+8
The square of \sqrt{3} is 3.
6+2\sqrt{3}+8\sqrt{3}+8
Multiply 2 and 3 to get 6.
6+10\sqrt{3}+8
Combine 2\sqrt{3} and 8\sqrt{3} to get 10\sqrt{3}.
14+10\sqrt{3}
Add 6 and 8 to get 14.