Evaluate
6\left(\sqrt{3}+2\right)\approx 22.392304845
Expand
6 \sqrt{3} + 12 = 22.392304845
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\left(\sqrt{3}\right)^{2}+6\sqrt{3}+9
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(\sqrt{3}+3\right)^{2}.
3+6\sqrt{3}+9
The square of \sqrt{3} is 3.
12+6\sqrt{3}
Add 3 and 9 to get 12.
\left(\sqrt{3}\right)^{2}+6\sqrt{3}+9
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(\sqrt{3}+3\right)^{2}.
3+6\sqrt{3}+9
The square of \sqrt{3} is 3.
12+6\sqrt{3}
Add 3 and 9 to get 12.
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