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\left(\sqrt{3}\right)^{2}-\sqrt{3}+2\sqrt{3}-2
Apply the distributive property by multiplying each term of \sqrt{3}+2 by each term of \sqrt{3}-1.
3-\sqrt{3}+2\sqrt{3}-2
The square of \sqrt{3} is 3.
3+\sqrt{3}-2
Combine -\sqrt{3} and 2\sqrt{3} to get \sqrt{3}.
1+\sqrt{3}
Subtract 2 from 3 to get 1.