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\left(\sqrt{3}\right)^{2}+\sqrt{3}+2\sqrt{3}+2
Apply the distributive property by multiplying each term of \sqrt{3}+2 by each term of \sqrt{3}+1.
3+\sqrt{3}+2\sqrt{3}+2
The square of \sqrt{3} is 3.
3+3\sqrt{3}+2
Combine \sqrt{3} and 2\sqrt{3} to get 3\sqrt{3}.
5+3\sqrt{3}
Add 3 and 2 to get 5.