Evaluate
4\sqrt{3}+7\approx 13.92820323
Expand
4 \sqrt{3} + 7 = 13.92820323
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\left(\sqrt{3}\right)^{2}+4\sqrt{3}+4
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(\sqrt{3}+2\right)^{2}.
3+4\sqrt{3}+4
The square of \sqrt{3} is 3.
7+4\sqrt{3}
Add 3 and 4 to get 7.
\left(\sqrt{3}\right)^{2}+4\sqrt{3}+4
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(\sqrt{3}+2\right)^{2}.
3+4\sqrt{3}+4
The square of \sqrt{3} is 3.
7+4\sqrt{3}
Add 3 and 4 to get 7.
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