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\left(\sqrt{3}\right)^{2}-4\sqrt{3}+\sqrt{3}-4
Apply the distributive property by multiplying each term of \sqrt{3}+1 by each term of \sqrt{3}-4.
3-4\sqrt{3}+\sqrt{3}-4
The square of \sqrt{3} is 3.
3-3\sqrt{3}-4
Combine -4\sqrt{3} and \sqrt{3} to get -3\sqrt{3}.
-1-3\sqrt{3}
Subtract 4 from 3 to get -1.