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\left(\sqrt{3}\right)^{2}-1-\sqrt{16}+\left(\frac{1}{2}\right)^{-1}
Consider \left(\sqrt{3}+1\right)\left(\sqrt{3}-1\right). Multiplication can be transformed into difference of squares using the rule: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}. Square 1.
3-1-\sqrt{16}+\left(\frac{1}{2}\right)^{-1}
The square of \sqrt{3} is 3.
2-\sqrt{16}+\left(\frac{1}{2}\right)^{-1}
Subtract 1 from 3 to get 2.
2-4+\left(\frac{1}{2}\right)^{-1}
Calculate the square root of 16 and get 4.
-2+\left(\frac{1}{2}\right)^{-1}
Subtract 4 from 2 to get -2.
-2+2
Calculate \frac{1}{2} to the power of -1 and get 2.
0
Add -2 and 2 to get 0.