Evaluate
2\left(\sqrt{3}+2\right)\approx 7.464101615
Expand
2 \sqrt{3} + 4 = 7.464101615
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\left(\sqrt{3}\right)^{2}+2\sqrt{3}+1
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(\sqrt{3}+1\right)^{2}.
3+2\sqrt{3}+1
The square of \sqrt{3} is 3.
4+2\sqrt{3}
Add 3 and 1 to get 4.
\left(\sqrt{3}\right)^{2}+2\sqrt{3}+1
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(\sqrt{3}+1\right)^{2}.
3+2\sqrt{3}+1
The square of \sqrt{3} is 3.
4+2\sqrt{3}
Add 3 and 1 to get 4.
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