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2\sqrt{3}-4\sqrt{5}-\left(3\sqrt{3}-4\sqrt{65}\right)
Factor 12=2^{2}\times 3. Rewrite the square root of the product \sqrt{2^{2}\times 3} as the product of square roots \sqrt{2^{2}}\sqrt{3}. Take the square root of 2^{2}.
2\sqrt{3}-4\sqrt{5}-3\sqrt{3}-\left(-4\sqrt{65}\right)
To find the opposite of 3\sqrt{3}-4\sqrt{65}, find the opposite of each term.
-\sqrt{3}-4\sqrt{5}-\left(-4\sqrt{65}\right)
Combine 2\sqrt{3} and -3\sqrt{3} to get -\sqrt{3}.
-\sqrt{3}-4\sqrt{5}+4\sqrt{65}
The opposite of -4\sqrt{65} is 4\sqrt{65}.