Solve (sqrt{1-019}+03^2-6/25):(-3)=

$$( \sqrt { 1 - 019 } + 03 ^ { 2 } - \frac { 6 } { 25 } ) : ( - 3 ) =$$

Evaluate

$$-\frac{19}{75}\approx -0.253333333$$

Solution Steps

Multiply 0 and 19 to get 0.

$$\frac{\sqrt{1-0}+0\times 3^{2}-\frac{6}{25}}{-3}$$

Subtract 0 from 1 to get 1.

$$\frac{\sqrt{1}+0\times 3^{2}-\frac{6}{25}}{-3}$$

Calculate the square root of 1 and get 1.

$$\frac{1+0\times 3^{2}-\frac{6}{25}}{-3}$$

Calculate 3 to the power of 2 and get 9.

$$\frac{1+0\times 9-\frac{6}{25}}{-3}$$

Multiply 0 and 9 to get 0.

$$\frac{1+0-\frac{6}{25}}{-3}$$

Add 1 and 0 to get 1.

$$\frac{1-\frac{6}{25}}{-3}$$

Convert 1 to fraction \frac{25}{25}.

$$\frac{\frac{25}{25}-\frac{6}{25}}{-3}$$

Since \frac{25}{25} and \frac{6}{25} have the same denominator, subtract them by subtracting their numerators.

$$\frac{\frac{25-6}{25}}{-3}$$

Subtract 6 from 25 to get 19.

$$\frac{\frac{19}{25}}{-3}$$

Express \frac{\frac{19}{25}}{-3} as a single fraction.

$$\frac{19}{25\left(-3\right)}$$

Multiply 25 and -3 to get -75.

$$\frac{19}{-75}$$

Fraction \frac{19}{-75} can be rewritten as -\frac{19}{75} by extracting the negative sign.

$$-\frac{19}{75}$$

Factor

$$-\frac{19}{75} = -0.25333333333333335$$