Solve (sqrt{1-0,19}+0,3^2-6/25):(-3)=

$$( \sqrt { 1 - 0,19 } + 0,3 ^ { 2 } - 6 / 25 ) : ( - 3 ) =$$

Evaluate

$$-0,22$$

Solution Steps

Subtract 0,19 from 1 to get 0,81.

$$\frac{\sqrt{0,81}+0\times 3^{2}-\frac{6}{25}}{-3}$$

Calculate the square root of 0,81 and get 0,9.

$$\frac{0,9+0\times 3^{2}-\frac{6}{25}}{-3}$$

Calculate 3 to the power of 2 and get 9.

$$\frac{0,9+0\times 9-\frac{6}{25}}{-3}$$

Multiply 0 and 9 to get 0.

$$\frac{0,9+0-\frac{6}{25}}{-3}$$

Add 0,9 and 0 to get 0,9.

$$\frac{0,9-\frac{6}{25}}{-3}$$

Convert decimal number 0,9 to fraction \frac{9}{10}.

$$\frac{\frac{9}{10}-\frac{6}{25}}{-3}$$

Least common multiple of 10 and 25 is 50. Convert \frac{9}{10} and \frac{6}{25} to fractions with denominator 50.

$$\frac{\frac{45}{50}-\frac{12}{50}}{-3}$$

Since \frac{45}{50} and \frac{12}{50} have the same denominator, subtract them by subtracting their numerators.

$$\frac{\frac{45-12}{50}}{-3}$$

Subtract 12 from 45 to get 33.

$$\frac{\frac{33}{50}}{-3}$$

Express \frac{\frac{33}{50}}{-3} as a single fraction.

$$\frac{33}{50\left(-3\right)}$$

Multiply 50 and -3 to get -150.

$$\frac{33}{-150}$$

Reduce the fraction \frac{33}{-150} to lowest terms by extracting and canceling out 3.

$$-\frac{11}{50}$$

Factor

$$-0,22$$